5x+(3x-2)=4x+(x-1)

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Solution for 5x+(3x-2)=4x+(x-1) equation: 



5x+(3x-2)=4x+(x-1)

We move all terms to the left:

5x+(3x-2)-(4x+(x-1))=0

We get rid of parentheses

5x+3x-(4x+(x-1))-2=0



We calculate terms in parentheses: -(4x+(x-1)), so:

4x+(x-1)

We get rid of parentheses

4x+x-1

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We add all the numbers together, and all the variables

8x-(5x-1)-2=0

We get rid of parentheses

8x-5x+1-2=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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