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5x+(4-2x)=9-(x-6)
We move all terms to the left:
5x+(4-2x)-(9-(x-6))=0
We add all the numbers together, and all the variables
5x+(-2x+4)-(9-(x-6))=0
We get rid of parentheses
5x-2x-(9-(x-6))+4=0
We calculate terms in parentheses: -(9-(x-6)), so:We add all the numbers together, and all the variables
9-(x-6)
determiningTheFunctionDomain -(x-6)+9
We get rid of parentheses
-x+6+9
We add all the numbers together, and all the variables
-1x+15
Back to the equation:
-(-1x+15)
3x-(-1x+15)+4=0
We get rid of parentheses
3x+1x-15+4=0
We add all the numbers together, and all the variables
4x-11=0
We move all terms containing x to the left, all other terms to the right
4x=11
x=11/4
x=2+3/4
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