5x+(40-2(x+3))=9x-2

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Solution for 5x+(40-2(x+3))=9x-2 equation: 



5x+(40-2(x+3))=9x-2

We move all terms to the left:

5x+(40-2(x+3))-(9x-2)=0

We get rid of parentheses

5x+(40-2(x+3))-9x+2=0



We calculate terms in parentheses: +(40-2(x+3)), so:

40-2(x+3)

determiningTheFunctionDomain
-2(x+3)+40

We multiply parentheses

-2x-6+40

We add all the numbers together, and all the variables

-2x+34

Back to the equation:

+(-2x+34)



We add all the numbers together, and all the variables

-4x+(-2x+34)+2=0

We get rid of parentheses

-4x-2x+34+2=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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