5x+(x-2(x+4))=0

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Solution for 5x+(x-2(x+4))=0 equation: 



5x+(x-2(x+4))=0



We calculate terms in parentheses: +(x-2(x+4)), so:

x-2(x+4)

We multiply parentheses

x-2x-8

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

+(-1x-8)



We get rid of parentheses

5x-1x-8=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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