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5x+-2(x-4)+-3=-2(2x-3)-+4
We move all terms to the left:
5x+-2(x-4)+-3-(-2(2x-3)-+4)=0
We add all the numbers together, and all the variables
5x-2(x-4)-(-2(2x-3)-+4)=0
We use the square of the difference formula
5x-2(x-4)-(-2(2x-3)-4)=0
We multiply parentheses
5x-2x-(-2(2x-3)-4)+8=0
We calculate terms in parentheses: -(-2(2x-3)-4), so:We add all the numbers together, and all the variables
-2(2x-3)-4
We multiply parentheses
-4x+6-4
We add all the numbers together, and all the variables
-4x+2
Back to the equation:
-(-4x+2)
3x-(-4x+2)+8=0
We get rid of parentheses
3x+4x-2+8=0
We add all the numbers together, and all the variables
7x+6=0
We move all terms containing x to the left, all other terms to the right
7x=-6
x=-6/7
x=-6/7
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