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5x+1+3(x+7)=2(x-3)
We move all terms to the left:
5x+1+3(x+7)-(2(x-3))=0
We multiply parentheses
5x+3x-(2(x-3))+21+1=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
8x-(2x-6)+22=0
We get rid of parentheses
8x-2x+6+22=0
We add all the numbers together, and all the variables
6x+28=0
We move all terms containing x to the left, all other terms to the right
6x=-28
x=-28/6
x=-4+2/3
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