5x+1-(x-4)+3=4(x+2)

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Solution for 5x+1-(x-4)+3=4(x+2) equation: 



5x+1-(x-4)+3=4(x+2)

We move all terms to the left:

5x+1-(x-4)+3-(4(x+2))=0

We add all the numbers together, and all the variables

5x-(x-4)-(4(x+2))+4=0

We get rid of parentheses

5x-x-(4(x+2))+4+4=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

4x-(4x+8)+8=0

We get rid of parentheses

4x-4x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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