5x+1-(x-4)=4(x+2)

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Solution for 5x+1-(x-4)=4(x+2) equation:


Simplifying
5x + 1 + -1(x + -4) = 4(x + 2)

Reorder the terms:
5x + 1 + -1(-4 + x) = 4(x + 2)
5x + 1 + (-4 * -1 + x * -1) = 4(x + 2)
5x + 1 + (4 + -1x) = 4(x + 2)

Reorder the terms:
1 + 4 + 5x + -1x = 4(x + 2)

Combine like terms: 1 + 4 = 5
5 + 5x + -1x = 4(x + 2)

Combine like terms: 5x + -1x = 4x
5 + 4x = 4(x + 2)

Reorder the terms:
5 + 4x = 4(2 + x)
5 + 4x = (2 * 4 + x * 4)
5 + 4x = (8 + 4x)

Add '-4x' to each side of the equation.
5 + 4x + -4x = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
5 + 0 = 8 + 4x + -4x
5 = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
5 = 8 + 0
5 = 8

Solving
5 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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