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5x+1/2x=9
We move all terms to the left:
5x+1/2x-(9)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
5x*2x-9*2x+1=0
Wy multiply elements
10x^2-18x+1=0
a = 10; b = -18; c = +1;
Δ = b2-4ac
Δ = -182-4·10·1
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{71}}{2*10}=\frac{18-2\sqrt{71}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{71}}{2*10}=\frac{18+2\sqrt{71}}{20} $
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