5x+1/4(12x+28)=4(2x+1)+3

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Solution for 5x+1/4(12x+28)=4(2x+1)+3 equation:



5x+1/4(12x+28)=4(2x+1)+3
We move all terms to the left:
5x+1/4(12x+28)-(4(2x+1)+3)=0
Domain of the equation: 4(12x+28)!=0
x∈R
We multiply all the terms by the denominator
5x*4(12x+28)-((4(2x+1)+3))*4(12x+28)+1=0
We calculate terms in parentheses: -((4(2x+1)+3))*4(12x+28), so:
(4(2x+1)+3))*4(12x+28
Wy multiply elements
20x^2(1-((4(2x+1)+3))*4(12x+28)+1=0

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