5x+1/x-3=20x+39/4x-5

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Solution for 5x+1/x-3=20x+39/4x-5 equation: 



5x+1/x-3=20x+39/4x-5

We move all terms to the left:

5x+1/x-3-(20x+39/4x-5)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 4x-5)!=0

x∈R



We get rid of parentheses

5x+1/x-20x-39/4x+5-3=0

We calculate fractions


5x-20x+4x/4x^2+(-39x)/4x^2+5-3=0

We add all the numbers together, and all the variables

-15x+4x/4x^2+(-39x)/4x^2+2=0

We multiply all the terms by the denominator


-15x*4x^2+4x+(-39x)+2*4x^2=0

We add all the numbers together, and all the variables

4x-15x*4x^2+(-39x)+2*4x^2=0

Wy multiply elements

-60x^3+8x^2+4x+(-39x)=0

We get rid of parentheses

-60x^3+8x^2+4x-39x=0

We do not support expression: x^3

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