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5x+10+x=3(2x+4)
We move all terms to the left:
5x+10+x-(3(2x+4))=0
We add all the numbers together, and all the variables
6x-(3(2x+4))+10=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
6x-6x-12+10=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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