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5x+11+3x=3(x+4)-1
We move all terms to the left:
5x+11+3x-(3(x+4)-1)=0
We add all the numbers together, and all the variables
8x-(3(x+4)-1)+11=0
We calculate terms in parentheses: -(3(x+4)-1), so:We get rid of parentheses
3(x+4)-1
We multiply parentheses
3x+12-1
We add all the numbers together, and all the variables
3x+11
Back to the equation:
-(3x+11)
8x-3x-11+11=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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