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5x+11=1/216x-20
We move all terms to the left:
5x+11-(1/216x-20)=0
Domain of the equation: 216x-20)!=0We get rid of parentheses
x∈R
5x-1/216x+20+11=0
We multiply all the terms by the denominator
5x*216x+20*216x+11*216x-1=0
Wy multiply elements
1080x^2+4320x+2376x-1=0
We add all the numbers together, and all the variables
1080x^2+6696x-1=0
a = 1080; b = 6696; c = -1;
Δ = b2-4ac
Δ = 66962-4·1080·(-1)
Δ = 44840736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44840736}=\sqrt{144*311394}=\sqrt{144}*\sqrt{311394}=12\sqrt{311394}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6696)-12\sqrt{311394}}{2*1080}=\frac{-6696-12\sqrt{311394}}{2160} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6696)+12\sqrt{311394}}{2*1080}=\frac{-6696+12\sqrt{311394}}{2160} $
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