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5x+12+4x=4(2x+5)=
We move all terms to the left:
5x+12+4x-(4(2x+5))=0
We add all the numbers together, and all the variables
9x-(4(2x+5))+12=0
We calculate terms in parentheses: -(4(2x+5)), so:We get rid of parentheses
4(2x+5)
We multiply parentheses
8x+20
Back to the equation:
-(8x+20)
9x-8x-20+12=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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