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5x+15+4x=6x-3x(x+9)
We move all terms to the left:
5x+15+4x-(6x-3x(x+9))=0
We add all the numbers together, and all the variables
9x-(6x-3x(x+9))+15=0
We calculate terms in parentheses: -(6x-3x(x+9)), so:We get rid of parentheses
6x-3x(x+9)
We multiply parentheses
-3x^2+6x-27x
We add all the numbers together, and all the variables
-3x^2-21x
Back to the equation:
-(-3x^2-21x)
3x^2+21x+9x+15=0
We add all the numbers together, and all the variables
3x^2+30x+15=0
a = 3; b = 30; c = +15;
Δ = b2-4ac
Δ = 302-4·3·15
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-12\sqrt{5}}{2*3}=\frac{-30-12\sqrt{5}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+12\sqrt{5}}{2*3}=\frac{-30+12\sqrt{5}}{6} $
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