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5x+15-2x=10(x+5)-35*
We move all terms to the left:
5x+15-2x-(10(x+5)-35*)=0
We add all the numbers together, and all the variables
3x-(10(x+5)-35*)+15=0
We calculate terms in parentheses: -(10(x+5)-35*), so:We get rid of parentheses
10(x+5)-35*
We add all the numbers together, and all the variables
10(x+5)
We multiply parentheses
10x+50
Back to the equation:
-(10x+50)
3x-10x-50+15=0
We add all the numbers together, and all the variables
-7x-35=0
We move all terms containing x to the left, all other terms to the right
-7x=35
x=35/-7
x=-5
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