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5x+15=1-(x-3)
We move all terms to the left:
5x+15-(1-(x-3))=0
We calculate terms in parentheses: -(1-(x-3)), so:We get rid of parentheses
1-(x-3)
determiningTheFunctionDomain -(x-3)+1
We get rid of parentheses
-x+3+1
We add all the numbers together, and all the variables
-1x+4
Back to the equation:
-(-1x+4)
5x+1x-4+15=0
We add all the numbers together, and all the variables
6x+11=0
We move all terms containing x to the left, all other terms to the right
6x=-11
x=-11/6
x=-1+5/6
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