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5x+16+4/5x-26=106
We move all terms to the left:
5x+16+4/5x-26-(106)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
5x+4/5x-116=0
We multiply all the terms by the denominator
5x*5x-116*5x+4=0
Wy multiply elements
25x^2-580x+4=0
a = 25; b = -580; c = +4;
Δ = b2-4ac
Δ = -5802-4·25·4
Δ = 336000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336000}=\sqrt{1600*210}=\sqrt{1600}*\sqrt{210}=40\sqrt{210}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-580)-40\sqrt{210}}{2*25}=\frac{580-40\sqrt{210}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-580)+40\sqrt{210}}{2*25}=\frac{580+40\sqrt{210}}{50} $
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