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5x+2(1-x)=2(2x+1)-1x
We move all terms to the left:
5x+2(1-x)-(2(2x+1)-1x)=0
We add all the numbers together, and all the variables
5x+2(-1x+1)-(2(2x+1)-1x)=0
We multiply parentheses
5x-2x-(2(2x+1)-1x)+2=0
We calculate terms in parentheses: -(2(2x+1)-1x), so:We add all the numbers together, and all the variables
2(2x+1)-1x
We add all the numbers together, and all the variables
-1x+2(2x+1)
We multiply parentheses
-1x+4x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-(3x+2)+2=0
We get rid of parentheses
3x-3x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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