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5x+2(2x-3)=14+2(3+x)
We move all terms to the left:
5x+2(2x-3)-(14+2(3+x))=0
We add all the numbers together, and all the variables
5x+2(2x-3)-(14+2(x+3))=0
We multiply parentheses
5x+4x-(14+2(x+3))-6=0
We calculate terms in parentheses: -(14+2(x+3)), so:We add all the numbers together, and all the variables
14+2(x+3)
determiningTheFunctionDomain 2(x+3)+14
We multiply parentheses
2x+6+14
We add all the numbers together, and all the variables
2x+20
Back to the equation:
-(2x+20)
9x-(2x+20)-6=0
We get rid of parentheses
9x-2x-20-6=0
We add all the numbers together, and all the variables
7x-26=0
We move all terms containing x to the left, all other terms to the right
7x=26
x=26/7
x=3+5/7
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