5x+2(3x-1)=5-4(x-2)

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Solution for 5x+2(3x-1)=5-4(x-2) equation: 



5x+2(3x-1)=5-4(x-2)

We move all terms to the left:

5x+2(3x-1)-(5-4(x-2))=0

We multiply parentheses

5x+6x-(5-4(x-2))-2=0



We calculate terms in parentheses: -(5-4(x-2)), so:

5-4(x-2)

determiningTheFunctionDomain
-4(x-2)+5

We multiply parentheses

-4x+8+5

We add all the numbers together, and all the variables

-4x+13

Back to the equation:

-(-4x+13)



We add all the numbers together, and all the variables

11x-(-4x+13)-2=0

We get rid of parentheses

11x+4x-13-2=0

We add all the numbers together, and all the variables

15x-15=0

We move all terms containing x to the left, all other terms to the right

15x=15

x=15/15

x=1

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