5x+2(3x-4)=20

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Solution for 5x+2(3x-4)=20 equation: 



5x+2(3x-4)=20

We move all terms to the left:

5x+2(3x-4)-(20)=0

We multiply parentheses

5x+6x-8-20=0

We add all the numbers together, and all the variables

11x-28=0

We move all terms containing x to the left, all other terms to the right

11x=28

x=28/11

x=2+6/11

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