5x+2(3x-5)=-4x-3(-2x+5)+20

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Solution for 5x+2(3x-5)=-4x-3(-2x+5)+20 equation: 



5x+2(3x-5)=-4x-3(-2x+5)+20

We move all terms to the left:

5x+2(3x-5)-(-4x-3(-2x+5)+20)=0

We multiply parentheses

5x+6x-(-4x-3(-2x+5)+20)-10=0



We calculate terms in parentheses: -(-4x-3(-2x+5)+20), so:

-4x-3(-2x+5)+20

We multiply parentheses

-4x+6x-15+20

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

11x-(2x+5)-10=0

We get rid of parentheses

11x-2x-5-10=0

We add all the numbers together, and all the variables

9x-15=0

We move all terms containing x to the left, all other terms to the right

9x=15

x=15/9

x=1+2/3

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