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5x+2(4x-4)=3(2x-1)
We move all terms to the left:
5x+2(4x-4)-(3(2x-1))=0
We multiply parentheses
5x+8x-(3(2x-1))-8=0
We calculate terms in parentheses: -(3(2x-1)), so:We add all the numbers together, and all the variables
3(2x-1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
13x-(6x-3)-8=0
We get rid of parentheses
13x-6x+3-8=0
We add all the numbers together, and all the variables
7x-5=0
We move all terms containing x to the left, all other terms to the right
7x=5
x=5/7
x=5/7
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