5x+2(x-1)=3(x+4)+4(x-1)

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Solution for 5x+2(x-1)=3(x+4)+4(x-1) equation: 


Simplifying
5x + 2(x + -1) = 3(x + 4) + 4(x + -1)

Reorder the terms:
5x + 2(-1 + x) = 3(x + 4) + 4(x + -1)
5x + (-1 * 2 + x * 2) = 3(x + 4) + 4(x + -1)
5x + (-2 + 2x) = 3(x + 4) + 4(x + -1)

Reorder the terms:
-2 + 5x + 2x = 3(x + 4) + 4(x + -1)

Combine like terms: 5x + 2x = 7x
-2 + 7x = 3(x + 4) + 4(x + -1)

Reorder the terms:
-2 + 7x = 3(4 + x) + 4(x + -1)
-2 + 7x = (4 * 3 + x * 3) + 4(x + -1)
-2 + 7x = (12 + 3x) + 4(x + -1)

Reorder the terms:
-2 + 7x = 12 + 3x + 4(-1 + x)
-2 + 7x = 12 + 3x + (-1 * 4 + x * 4)
-2 + 7x = 12 + 3x + (-4 + 4x)

Reorder the terms:
-2 + 7x = 12 + -4 + 3x + 4x

Combine like terms: 12 + -4 = 8
-2 + 7x = 8 + 3x + 4x

Combine like terms: 3x + 4x = 7x
-2 + 7x = 8 + 7x

Add '-7x' to each side of the equation.
-2 + 7x + -7x = 8 + 7x + -7x

Combine like terms: 7x + -7x = 0
-2 + 0 = 8 + 7x + -7x
-2 = 8 + 7x + -7x

Combine like terms: 7x + -7x = 0
-2 = 8 + 0
-2 = 8

Solving
-2 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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