5x+2(x-3(x-2))=0

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Solution for 5x+2(x-3(x-2))=0 equation:


Simplifying
5x + 2(x + -3(x + -2)) = 0

Reorder the terms:
5x + 2(x + -3(-2 + x)) = 0
5x + 2(x + (-2 * -3 + x * -3)) = 0
5x + 2(x + (6 + -3x)) = 0

Reorder the terms:
5x + 2(6 + x + -3x) = 0

Combine like terms: x + -3x = -2x
5x + 2(6 + -2x) = 0
5x + (6 * 2 + -2x * 2) = 0
5x + (12 + -4x) = 0

Reorder the terms:
12 + 5x + -4x = 0

Combine like terms: 5x + -4x = 1x
12 + 1x = 0

Solving
12 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 1x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 1x = 0 + -12
1x = 0 + -12

Combine like terms: 0 + -12 = -12
1x = -12

Divide each side by '1'.
x = -12

Simplifying
x = -12

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