5x+2(x-7)=3(2x-4)+x-2

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Solution for 5x+2(x-7)=3(2x-4)+x-2 equation: 



5x+2(x-7)=3(2x-4)+x-2

We move all terms to the left:

5x+2(x-7)-(3(2x-4)+x-2)=0

We multiply parentheses

5x+2x-(3(2x-4)+x-2)-14=0



We calculate terms in parentheses: -(3(2x-4)+x-2), so:

3(2x-4)+x-2

We add all the numbers together, and all the variables

x+3(2x-4)-2

We multiply parentheses

x+6x-12-2

We add all the numbers together, and all the variables

7x-14

Back to the equation:

-(7x-14)



We add all the numbers together, and all the variables

7x-(7x-14)-14=0

We get rid of parentheses

7x-7x+14-14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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