5x+2(x-9)=3(x-4)+x

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Solution for 5x+2(x-9)=3(x-4)+x equation: 



5x+2(x-9)=3(x-4)+x

We move all terms to the left:

5x+2(x-9)-(3(x-4)+x)=0

We multiply parentheses

5x+2x-(3(x-4)+x)-18=0



We calculate terms in parentheses: -(3(x-4)+x), so:

3(x-4)+x

We add all the numbers together, and all the variables

x+3(x-4)

We multiply parentheses

x+3x-12

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

7x-(4x-12)-18=0

We get rid of parentheses

7x-4x+12-18=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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