5x+2+-3(x+2)=-2(x+1)+5(x+-2)

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Solution for 5x+2+-3(x+2)=-2(x+1)+5(x+-2) equation: 



5x+2+-3(x+2)=-2(x+1)+5(x+-2)

We move all terms to the left:

5x+2+-3(x+2)-(-2(x+1)+5(x+-2))=0

We add all the numbers together, and all the variables

5x-3(x+2)-(-2(x+1)+5(x-2))+2+=0

We add all the numbers together, and all the variables

5x-3(x+2)-(-2(x+1)+5(x-2))=0

We multiply parentheses

5x-3x-(-2(x+1)+5(x-2))-6=0



We calculate terms in parentheses: -(-2(x+1)+5(x-2)), so:

-2(x+1)+5(x-2)

We multiply parentheses

-2x+5x-2-10

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

2x-(3x-12)-6=0

We get rid of parentheses

2x-3x+12-6=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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