5x+2/3(6x-4)=7(x+1)

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Solution for 5x+2/3(6x-4)=7(x+1) equation: 


x in (-oo:+oo)

(2/3)*(6*x-4)+5*x = 7*(x+1) // - 7*(x+1)

(2/3)*(6*x-4)-(7*(x+1))+5*x = 0

(2/3)*(6*x-4)-7*(x+1)+5*x = 0

2/3*(6*x-4)-7*(x+1)+5*x = 0

2/3*(6*x-4)-7*(x+1)+5*x = 0

5*x-3*x-29/3 = 0

2*x-29/3 = 0

2*x-29/3 = 0

2*x-29/3 = 0 // + 29/3

2*x = 29/3 // : 2

x = 29/3/2

x = 29/6

x = 29/6

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