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5x+2/x-4=10x/2x-3
We move all terms to the left:
5x+2/x-4-(10x/2x-3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-3)!=0We get rid of parentheses
x∈R
5x+2/x-10x/2x+3-4=0
We calculate fractions
(-10x^2)/2x^2+5x+4x/2x^2+3-4=0
We add all the numbers together, and all the variables
(-10x^2)/2x^2+5x+4x/2x^2-1=0
We multiply all the terms by the denominator
(-10x^2)+5x*2x^2+4x-1*2x^2=0
We add all the numbers together, and all the variables
(-10x^2)+4x+5x*2x^2-1*2x^2=0
Wy multiply elements
(-10x^2)+10x^3-2x^2+4x=0
We get rid of parentheses
-10x^2+10x^3-2x^2+4x=0
We do not support expression: x^3
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