5x+20-3(4x+3)=7(x+4)

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Solution for 5x+20-3(4x+3)=7(x+4) equation: 



5x+20-3(4x+3)=7(x+4)

We move all terms to the left:

5x+20-3(4x+3)-(7(x+4))=0

We multiply parentheses

5x-12x-(7(x+4))-9+20=0



We calculate terms in parentheses: -(7(x+4)), so:

7(x+4)

We multiply parentheses

7x+28

Back to the equation:

-(7x+28)



We add all the numbers together, and all the variables

-7x-(7x+28)+11=0

We get rid of parentheses

-7x-7x-28+11=0

We add all the numbers together, and all the variables

-14x-17=0

We move all terms containing x to the left, all other terms to the right

-14x=17

x=17/-14

x=-1+3/14

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