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5x+20/(1x-9)=10
We move all terms to the left:
5x+20/(1x-9)-(10)=0
Domain of the equation: (1x-9)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=9
x∈R
5x+20/(x-9)-10=0
We multiply all the terms by the denominator
5x*(x-9)-10*(x-9)+20=0
We multiply parentheses
5x^2-45x-10x+90+20=0
We add all the numbers together, and all the variables
5x^2-55x+110=0
a = 5; b = -55; c = +110;
Δ = b2-4ac
Δ = -552-4·5·110
Δ = 825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{825}=\sqrt{25*33}=\sqrt{25}*\sqrt{33}=5\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-5\sqrt{33}}{2*5}=\frac{55-5\sqrt{33}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+5\sqrt{33}}{2*5}=\frac{55+5\sqrt{33}}{10} $
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