5x+20=3x-4(x-2)

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Solution for 5x+20=3x-4(x-2) equation: 



5x+20=3x-4(x-2)

We move all terms to the left:

5x+20-(3x-4(x-2))=0



We calculate terms in parentheses: -(3x-4(x-2)), so:

3x-4(x-2)

We multiply parentheses

3x-4x+8

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We get rid of parentheses

5x+1x-8+20=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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