5x+20x+12=(3x+2)2

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Solution for 5x+20x+12=(3x+2)2 equation: 



5x+20x+12=(3x+2)2

We move all terms to the left:

5x+20x+12-((3x+2)2)=0

We add all the numbers together, and all the variables

25x-((3x+2)2)+12=0



We calculate terms in parentheses: -((3x+2)2), so:

(3x+2)2

We multiply parentheses

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

25x-6x-4+12=0

We add all the numbers together, and all the variables

19x+8=0

We move all terms containing x to the left, all other terms to the right

19x=-8

x=-8/19

x=-8/19

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