5x+25-4x-(2x+10)+15(5-2x)=10-(10x+5)+4x-5

Solution for 5x+25-4x-(2x+10)+15(5-2x)=10-(10x+5)+4x-5 equation:

5x+25-4x-(2x+10)+15(5-2x)=10-(10x+5)+4x-5

We move all terms to the left:

5x+25-4x-(2x+10)+15(5-2x)-(10-(10x+5)+4x-5)=0

We add all the numbers together, and all the variables

5x-4x-(2x+10)+15(-2x+5)-(10-(10x+5)+4x-5)+25=0

We add all the numbers together, and all the variables

x-(2x+10)+15(-2x+5)-(10-(10x+5)+4x-5)+25=0

We multiply parentheses

x-(2x+10)-30x-(10-(10x+5)+4x-5)+75+25=0

We get rid of parentheses

x-2x-30x-(10-(10x+5)+4x-5)-10+75+25=0


We calculate terms in parentheses: -(10-(10x+5)+4x-5), so:

10-(10x+5)+4x-5

determiningTheFunctionDomain
-(10x+5)+4x+10-5

We add all the numbers together, and all the variables

4x-(10x+5)+5

We get rid of parentheses

4x-10x-5+5

We add all the numbers together, and all the variables

-6x

Back to the equation:

-(-6x)


We add all the numbers together, and all the variables

-31x-(-6x)+90=0

We get rid of parentheses

-31x+6x+90=0

We add all the numbers together, and all the variables

-25x+90=0

We move all terms containing x to the left, all other terms to the right

-25x=-90

x=-90/-25

x=3+3/5