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5x+26=4-3/2x
We move all terms to the left:
5x+26-(4-3/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x-(-3/2x+4)+26=0
We get rid of parentheses
5x+3/2x-4+26=0
We multiply all the terms by the denominator
5x*2x-4*2x+26*2x+3=0
Wy multiply elements
10x^2-8x+52x+3=0
We add all the numbers together, and all the variables
10x^2+44x+3=0
a = 10; b = 44; c = +3;
Δ = b2-4ac
Δ = 442-4·10·3
Δ = 1816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1816}=\sqrt{4*454}=\sqrt{4}*\sqrt{454}=2\sqrt{454}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-2\sqrt{454}}{2*10}=\frac{-44-2\sqrt{454}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+2\sqrt{454}}{2*10}=\frac{-44+2\sqrt{454}}{20} $
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