5x+27=2(x+5)-10

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Solution for 5x+27=2(x+5)-10 equation: 



5x+27=2(x+5)-10

We move all terms to the left:

5x+27-(2(x+5)-10)=0



We calculate terms in parentheses: -(2(x+5)-10), so:

2(x+5)-10

We multiply parentheses

2x+10-10

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

3x+27=0

We move all terms containing x to the left, all other terms to the right

3x=-27

x=-27/3

x=-9

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