5x+2=(1/2)4x+1+27

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Solution for 5x+2=(1/2)4x+1+27 equation:



5x+2=(1/2)4x+1+27
We move all terms to the left:
5x+2-((1/2)4x+1+27)=0
Domain of the equation: 2)4x+1+27)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
5x-((+1/2)4x+1+27)+2=0
We multiply all the terms by the denominator
5x*2)4x+1+27)-((+2*2)4x+1+27)+1=0
We add all the numbers together, and all the variables
5x*2)4x+1+27)-(44x+1+27)+1=0
Wy multiply elements
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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