5x+2=(1/2)4x+1+27

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Solution for 5x+2=(1/2)4x+1+27 equation: 



5x+2=(1/2)4x+1+27

We move all terms to the left:

5x+2-((1/2)4x+1+27)=0



Domain of the equation: 2)4x+1+27)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

5x-((+1/2)4x+1+27)+2=0

We multiply all the terms by the denominator


5x*2)4x+1+27)-((+2*2)4x+1+27)+1=0

We add all the numbers together, and all the variables

5x*2)4x+1+27)-(44x+1+27)+1=0

Wy multiply elements

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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