5x+2y=28;3x+2y=4

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Solution for 5x+2y=28;3x+2y=4 system of equations: 


  • /| 5*x+2*y-28 = 0| 3*x+2*y-4 = 0
  • We try to solve the equation: 5*x+2*y-28 = 0
  • 5*x+2*y-28 = 0 // - 5*x-28
  • 2*y = -(5*x-28) // : 2
  • y = (-(5*x-28))/2
  • y = (28-(5*x))/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*((28-(5*x))/2)+3*x-4 = 0| y = (28-(5*x))/2
  • (2*(28-5*x))/2+3*x-4 = 0
  • 28-2*x-4 = 0
  • 24-2*x = 0
  • 24-2*x = 0 // - 24
  • -2*x = -24 // : -2
  • x = -24/(-2)
  • x = 12
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (28-(5*x))/2: 
  • y = (28-(5*12))/2
  • y = (28-60)/2
  • y = -32/2
  • y = -16
  • We get a system of equations:
  • /| y = -16| x = 12

 

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