5x+3(2x-1)=1-4(x-2)

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Solution for 5x+3(2x-1)=1-4(x-2) equation: 



5x+3(2x-1)=1-4(x-2)

We move all terms to the left:

5x+3(2x-1)-(1-4(x-2))=0

We multiply parentheses

5x+6x-(1-4(x-2))-3=0



We calculate terms in parentheses: -(1-4(x-2)), so:

1-4(x-2)

determiningTheFunctionDomain
-4(x-2)+1

We multiply parentheses

-4x+8+1

We add all the numbers together, and all the variables

-4x+9

Back to the equation:

-(-4x+9)



We add all the numbers together, and all the variables

11x-(-4x+9)-3=0

We get rid of parentheses

11x+4x-9-3=0

We add all the numbers together, and all the variables

15x-12=0

We move all terms containing x to the left, all other terms to the right

15x=12

x=12/15

x=4/5

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