5x+3(2x-5)=11+3(x+2)

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Solution for 5x+3(2x-5)=11+3(x+2) equation: 



5x+3(2x-5)=11+3(x+2)

We move all terms to the left:

5x+3(2x-5)-(11+3(x+2))=0

We multiply parentheses

5x+6x-(11+3(x+2))-15=0



We calculate terms in parentheses: -(11+3(x+2)), so:

11+3(x+2)

determiningTheFunctionDomain
3(x+2)+11

We multiply parentheses

3x+6+11

We add all the numbers together, and all the variables

3x+17

Back to the equation:

-(3x+17)



We add all the numbers together, and all the variables

11x-(3x+17)-15=0

We get rid of parentheses

11x-3x-17-15=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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