5x+3(x+4)=4-3(x-1)-6

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Solution for 5x+3(x+4)=4-3(x-1)-6 equation: 



5x+3(x+4)=4-3(x-1)-6

We move all terms to the left:

5x+3(x+4)-(4-3(x-1)-6)=0

We multiply parentheses

5x+3x-(4-3(x-1)-6)+12=0



We calculate terms in parentheses: -(4-3(x-1)-6), so:

4-3(x-1)-6

determiningTheFunctionDomain
-3(x-1)+4-6

We add all the numbers together, and all the variables

-3(x-1)-2

We multiply parentheses

-3x+3-2

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

8x-(-3x+1)+12=0

We get rid of parentheses

8x+3x-1+12=0

We add all the numbers together, and all the variables

11x+11=0

We move all terms containing x to the left, all other terms to the right

11x=-11

x=-11/11

x=-1

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