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5x+3(x-2)=2(x+9)-12
We move all terms to the left:
5x+3(x-2)-(2(x+9)-12)=0
We multiply parentheses
5x+3x-(2(x+9)-12)-6=0
We calculate terms in parentheses: -(2(x+9)-12), so:We add all the numbers together, and all the variables
2(x+9)-12
We multiply parentheses
2x+18-12
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
8x-(2x+6)-6=0
We get rid of parentheses
8x-2x-6-6=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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