5x+3(x-3)=6(x+3)-2x+1

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Solution for 5x+3(x-3)=6(x+3)-2x+1 equation: 



5x+3(x-3)=6(x+3)-2x+1

We move all terms to the left:

5x+3(x-3)-(6(x+3)-2x+1)=0

We multiply parentheses

5x+3x-(6(x+3)-2x+1)-9=0



We calculate terms in parentheses: -(6(x+3)-2x+1), so:

6(x+3)-2x+1

We add all the numbers together, and all the variables

-2x+6(x+3)+1

We multiply parentheses

-2x+6x+18+1

We add all the numbers together, and all the variables

4x+19

Back to the equation:

-(4x+19)



We add all the numbers together, and all the variables

8x-(4x+19)-9=0

We get rid of parentheses

8x-4x-19-9=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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