5x+3+20x=2(10x-36)

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Solution for 5x+3+20x=2(10x-36) equation:



5x+3+20x=2(10x-36)
We move all terms to the left:
5x+3+20x-(2(10x-36))=0
We add all the numbers together, and all the variables
25x-(2(10x-36))+3=0
We calculate terms in parentheses: -(2(10x-36)), so:
2(10x-36)
We multiply parentheses
20x-72
Back to the equation:
-(20x-72)
We get rid of parentheses
25x-20x+72+3=0
We add all the numbers together, and all the variables
5x+75=0
We move all terms containing x to the left, all other terms to the right
5x=-75
x=-75/5
x=-15

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