5x+3-2x=10(x-4)

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Solution for 5x+3-2x=10(x-4) equation: 



5x+3-2x=10(x-4)

We move all terms to the left:

5x+3-2x-(10(x-4))=0

We add all the numbers together, and all the variables

3x-(10(x-4))+3=0



We calculate terms in parentheses: -(10(x-4)), so:

10(x-4)

We multiply parentheses

10x-40

Back to the equation:

-(10x-40)



We get rid of parentheses

3x-10x+40+3=0

We add all the numbers together, and all the variables

-7x+43=0

We move all terms containing x to the left, all other terms to the right

-7x=-43

x=-43/-7

x=6+1/7

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