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5x+3-3=2(x+3)-5
We move all terms to the left:
5x+3-3-(2(x+3)-5)=0
We add all the numbers together, and all the variables
5x-(2(x+3)-5)=0
We calculate terms in parentheses: -(2(x+3)-5), so:We get rid of parentheses
2(x+3)-5
We multiply parentheses
2x+6-5
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
5x-2x-1=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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