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5x+3/4x=58
We move all terms to the left:
5x+3/4x-(58)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
5x*4x-58*4x+3=0
Wy multiply elements
20x^2-232x+3=0
a = 20; b = -232; c = +3;
Δ = b2-4ac
Δ = -2322-4·20·3
Δ = 53584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{53584}=\sqrt{16*3349}=\sqrt{16}*\sqrt{3349}=4\sqrt{3349}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-232)-4\sqrt{3349}}{2*20}=\frac{232-4\sqrt{3349}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-232)+4\sqrt{3349}}{2*20}=\frac{232+4\sqrt{3349}}{40} $
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